Question

how many grams of of kcl must be added to 75 grams of water to produce a solution that is 2.25 molal​

Answer 1

If 1000- g of water contains =( 2.25 x 74.6) =167.85 g of KCl , then the solution will be 2.25 MOLAL solution.

So 75 g of water contains= 75/1000 x 168.75 =12.59 g of KCl.