Question

How many grams of potassium nitrate , KNO3 required to make 250 ml solution with a molarity of 0.40 M ?

Answer 1

Answer:

m=10.1g

Explanation:

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Answer 2

Given:

The volume of solution, V = 250 ml

The molarity of solution, M = 0.40 M

To Find:

The amount of potassium nitrate (KNO3) required to make the solution.

Calculation:

- Molar mass of KNO3, M. wt. = 101 gm

- We know that molarity is given as:

M = (w × 1000) / (M. wt × V)

⇒ w = M × (M. wt × V) / 1000

⇒ w = 0.4 × (101 × 250) / 1000

⇒ w = 10.1 gm

- So, the amount of potassium nitrate (KNO3) required to make the solution is 10.1 gm.