Question

how many grams of SO3will be produced from one mole of S8?

Answer 1

Hi friend,
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#640g

Solution :-

Reactions :- S8 + 8O2-----> 8SO2
1 mol 8 mol


2SO2 + O2(2)------> 2SO3

Therefore, wt of SO3 = number of moles × Molecular weight

So, 8×(32+3×16)g
= 8×80g
= 640g ( proved)

Thus , 640g of SO3 will produce from 1 mole of S8
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Answer 2

Answer : The mass of SO_3SO

3

produced are, 640 grams.

Solution : Given,

Moles of S_8S

8

= 1 mole

Molar mass of SO_3SO

3

= 80 g/mole

The balanced chemical reaction will be,

S_8+12O_2\rightarrow 8SO_3S

8

+12O

2

→8SO

3

From the balanced reaction, we conclude that

1 mole of S_8S

8

react to give 8 moles of SO_3SO

3

Now we have to calculate the mass of SO_3SO

3

\text{Mass of }SO_3=\text{Moles of }SO_3\times \text{Molar mass of }SO_3Mass of SO

3

=Moles of SO

3

×Molar mass of SO

3

\text{Mass of }SO_3=(8mole)\times (80g/mole)=640gMass of SO

3

=(8mole)×(80g/mole)=640g

Therefore, the mass of SO_3SO

3

produced are, 640 grams.