Question

how many grams of sodium will have the same number of atoms as 6 grams of magnesium​

Answer 1

Answer:

no.of atom of Na = no.of atom of Mg

$\frac{x}{23}\times6.022\times {10}^{23}\times1=\frac{6}{24}\times6.022\times{10}^{3} \times1$

$\frac{x}{23} = \frac{6}{24}$

$x = \frac{6 \times 23}{24}$

$x = \frac{23}{4}$

hope it help u