How many grams of water is produced when 2g of hydrogen and 8g of oxygen are reacted
Answers
9 grams
Explanation:
The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively.
2H2+O2→2H2O
2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water.
Hence, 44=1 g of hydrogen reacts with 432=8 g of oxygen to form 436=9 g of water.
9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.
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9g water will be produced by the reaction of 2 g Hydrogen and 8g oxygen.
Given: Mass of hydrogen taken = 2g
Mass of oxygen taken = 8g
To Find: The mass of water produced
Solution:
The reaction between hydrogen and oxygen to form water is given as :
H₂ + 1/2 O₂ → H₂O
The molecular mass of H₂ = 2 x atomic mass of H
The molecular mass of H₂ = 2g
The molecular mass of O₂ = 2 x Atomic mass of O
The molecular mass of O₂ = 32g
The molecular mass of H₂O = 2 x Atomic mass of H + Atomic mass of O
= 2 x 1 + 16
= 18g
H₂ + 1/2 O₂ → H₂O
2g 16g 18g
From the above equation, we can see that 2g of Hydrogen requires 16g of Oxygen to react with it to form 18g of Water.
Here, 8g of oxygen is given so oxygen will be the limiting reagent.
16g oxygen reacts with how many grams of hydrogen = 2g
1g oxygen will react with how many grams of hydrogen = 2/16
8g oxygen will react with how many grams of hydrogen =
= 1g
2g Hydrogen will form how many grams of water = 18g
1g Hydrogen will form how many grams of water = 18 / 2
= 9g
Therefore, 9g water will be produced by the reaction of 2 g Hydrogen and 8g oxygen.
Limiting reagent: The reactant that will be finished up entirely during the reaction and will not be left after the reaction is complete.