how many grams of water is required to make 115200000 g of oxygen
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1296 × 10⁵ g of water
Explanation:
Given: mass of oxygen = 1152 × 10⁵ g
Balanced reaction:
2H₂ + O₂ → 2H₂O
1 mole of oxygen reacts to produce 2 moles of water.
Moles of H₂O required:
1152 × 10⁵ × 2/32
= 72 × 10⁵ moles of H₂O
mass of H₂O = moles × molecular weight
= 72 × 10⁵ × 18
= 1296 × 10⁵ g of water
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