Question

How many H atoms are present in 25.6g of urea (NH2CONH2)

Answer 1

Answer:

Urea = NH2CONH2

M.wt = 60

5.6 g urea = 5.6/60 = 0.093 moles

1 mole of urea contains 4N atoms of H

0.093 moles contains 0.093 x 4N atoms of H

= 2.24 x 10^23 atoms of H

No of atoms of Nitrogen = half of the number of atoms of H

= 1.12 x 10^23 atoms of N

No of atoms of C or O = half of the number of atoms of N

= 0.56 x 10^23 atoms of C or O

= 5.6 x 10^22 atoms of C or O

Explanation:

Answer 2

Answer:

I got it this anwer this Shuplhurek acid