Question

2x-y=-1 and 2x+3y=11​

Answer 1

Answer:

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2x-y = -1

2x+1 =y --1equation

__________

2x+3y =11

Putting the value of y from 1equation,

2x+3[2x+1] =11

2x+6x+3 =11

8x +3=11

8x =11-3

8x =8

x=8/8

x=1

Putting the value of x in 1equation,

2(1)+1=y

2+1=y

3=y

_______,

x=1

y=3

I hope this this will help you

Answer 2

Answer

$\sf \dashrightarrow 2x - y = -1 \: \: --- (i)$

$\sf \dashrightarrow 2x + 3y = 11 \: \: --- (ii)$

By first equation,

$\sf \dashrightarrow 2x - y = -1$

$\sf \dashrightarrow 2x = -1 + y$

$\sf \dashrightarrow x = \dfrac{-1 + y}{2}$

Now, let's find the value of y by second equation.

$\sf \dashrightarrow 2x + 3y = 11$

$\sf \dashrightarrow 2 \bigg( \dfrac{-1 + y}{2} \bigg) + 3y = 11$

$\sf \dashrightarrow \dfrac{-2 + 2y}{2} + 3y = 11$

$\sf \dashrightarrow \dfrac{-2 + 2y + 6y}{2} = 11$

$\sf \dashrightarrow \dfrac{-2 + 8y}{2} = 11$

$\sf \dashrightarrow -2 + 8y = 11 \times 2$

$\sf \dashrightarrow -2 + 8y = 22$

$\sf \dashrightarrow 8y = 22 + 2$

$\sf \dashrightarrow 8y = 24$

$\sf \dashrightarrow y = \dfrac{24}{8}$

$\sf \dashrightarrow y = 3$

Now, let's find the value of x by first equation.

$\sf \dashrightarrow 2x - y = -1$

$\sf \dashrightarrow 2x - 3 = -1$

$\sf \dashrightarrow 2x = -1 + 3$

$\sf \dashrightarrow 2x = 2$

$\sf \dashrightarrow x = \dfrac{2}{2}$

$\sf \dashrightarrow x = 1$

Hence, the values of x and y are 1 and 3 respectively.