Question

How many images of himself can an observer see in a room whose ceiling and two adjacent walls are mirrors?

Answer 1

If two mirrors are placed at an angle Ф, number of images would be 

$n= \frac{360}{\phi}-1$

For the two adjacent mirrors on walls,
$n_1= \frac{360}{90}-1=4-1=3$

For one mirror on wall and other on ceiling,
$n_2= \frac{360}{90}-1=4-1=3$

For another mirror on wall and other on ceiling,
$n_3= \frac{360}{90}-1=4-1=3$

Total images = 3+3+3 = 9 images.

Answer 2

HOPE IT HELPS .
PLZ MARK ME AS BRAINLIEST.