How many integers between 199 and 599 are multiples of three
Answers
Answered by
4
1st multiple of 3 after 199 is 201
and last multiple before 599 is 597.
difference is 3 between each term.
so nth term is 597 and first term is 201
hence anth = a + (n-1)*3
597 = 201 +(n-1)3
396 =(n-1)3
132= n-1
n= 133
it is your required answer.
hope this will help you .
$
and last multiple before 599 is 597.
difference is 3 between each term.
so nth term is 597 and first term is 201
hence anth = a + (n-1)*3
597 = 201 +(n-1)3
396 =(n-1)3
132= n-1
n= 133
it is your required answer.
hope this will help you .
$
Anonymous:
thanks
Answered by
1
hello there!!!
First multiple of 3 b/ w 199 & 599 is 201 and last is 597
201, 204,207,............................597
here, first term a= 201
and second term, a2= 204
Common difference, d = a2- a
= 204 -201 =3
last term ,an or l = 597
an = a +( n-1) d
597= 201 +( n-1) 3
396 = 3n-3
399 = 3n
n = 399/3. = 133
No. of intergers b/w 199 & 599 are 131
HOPE IT HELPS YOU
First multiple of 3 b/ w 199 & 599 is 201 and last is 597
201, 204,207,............................597
here, first term a= 201
and second term, a2= 204
Common difference, d = a2- a
= 204 -201 =3
last term ,an or l = 597
an = a +( n-1) d
597= 201 +( n-1) 3
396 = 3n-3
399 = 3n
n = 399/3. = 133
No. of intergers b/w 199 & 599 are 131
HOPE IT HELPS YOU
Similar questions