Question

How many ions of calcium are present in 40 g of calcium carbonate?
(Aata h toh hi batana yr marks cut ho jyega)​

Answer 1

Correct option is B)

Given 3.2g CaO

atomic mass = 40+16

=56

moles of Ca ion =

56

3.2

=0.057

1 mol = 6.022×10

23

atoms of Ca ion

0.057mol=3.44×10

22

Ca ions

Answer 2

Answer:

Molar mass of calcium carbonate is 100g/mole

Its molecular mass =40 + 12 + (3 x 16) = 100 g

1 mole of Calcium Carbonate = 100 g of Calcium Carbonate

100 g of Calcium Carbonate has 3 moles of Oxygen atoms = 3 x 6.022 x 10²³ Oxygen atoms.

So, 200 g of Calcium Carbonate has 6 moles of Oxygen atoms = 6 x 6.022 x 10²³ Oxygen atoms.

When CaCO₃ dissociates it gives 2 calcium ions

CaCO₃→  Ca²⁺ + CO₃²⁻