Chemistry, asked by chiragmittal2009, 1 year ago

how many joules are absorbed by 75 grams of water that is warmed

Answers

Answered by ajayshotia

0

specific heat of wayer =4181 j /kg
wt.=75gms=75/1000=.075 kg
temp. change 0 to 50
heat absorbed =.075×4181×50=15678.75J
15.678kJ

Answered by yuvanchigurupati

0

Answer:

15.678KJ

Explanation:

specific heat of wayer =4181 j /kg

wt.=75gms=75/1000=.075 kg

temp. change 0 to 50

heat absorbed =.075×4181×50=3.75×4181

15.678kJ

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