Question

how many joules of heat is absorbed by water at 0°C

Answer 1

the heat(Q- in joules) needed to raise the temperature of the sample of water of mass M(in grams) by T(º celsius) is.....

Cp= specific heat of the water (4.18 J/g*ºC)

Q=M*Cp*∆T

So....

V=1000mL so M=1000mL*(1g/1mL)= 1000g water

Q=(1000g)(4.18J/g*ºC)(50-25)=104500 J or 104.5 kJ

Answer 2

When ice melts at 0 degrees C it draws 3.34×10^5 joule/kg heat from the substance it touches to get converted into water ... then the water at 0 degrees C draws or absorbs in 22.5 × 10^5 joule/kg heat from the substance it touches in order to vaporize and gets converted into water vapour.