Question

how many kg of CO2 is obtained by heating 1kg of90% MgCO3?​

Answer 1

Explanation:

MgCO3>>>>MgO+CO2

Given 1 kg MgCO3 which is 90% pure.

Thus real mass of MgCO3 is 90% of 1kg

=900g

Molecular masses

MgCO3=24×1+12×1+16×3=84

MgO=24×1+16×1=40

CO2=12×1+16×2=44

Thus 84 units (grams) of MgCO3 gives 44 units (grams) of CO2

Thus 900 units of MgCO3 will give

(90084×44) units of CO2

=approximately 471.43 units of CO2

Thus,

1kg, 90% pure MgCO3 will give approximately 471.43 grams of CO2

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