Question

how many kilo calories of heat is required to raise the temperature of 100g of water from 5°C to 95°C
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Answer 1

Answer:

m=100g,C=1calg

−1

o

C

−1

ΔT=(95−5)

o

C=90

o

C

Q=mCΔT

=100g×1calg

−1

o

C

−1

×90

o

C

=100×1×90cal

=9000cal=9kcal