How many lines can be drawn in a plane such that they are equidistant from three noncollinear points?
Answers
Answered by
0
Answer:
Let we have three non-collinear points A , B and C. To draw any line we need only two points. So total numbers of possible lines are 3. Hence from three noncollinear points we can draw three lines.
Answered by
5
The answer is always 3. According to the question, the answer boils down to finding the mid point of the altitudes and the perpendicular line passing through it.
Similar questions