Math, asked by poonamdogra61, 11 months ago

How many litres of vinegar should be mixed in a mixture (vinegar + water) of 60 litres in which initial ratio of vinegar to water is 1:4 so that the resulting mixture contains 35% of vinegar in it?

Answers

Answered by Muntazim
0
40 liters of vineger
Answered by raghavbkspheris
1

Answer:

Step-by-step explanation:

1:4

There is 1 part of vinegar and 4 part of water in a 60 L mixture

The amount of vinegar is 1/5x60 = 12 L

it means 1/5x60 = 20% of vinegar in 60 L mixture

The combination required is 35% vinegar and 65% water i.e.

35:65 = 7:13

The 1:4 mixture is to be converted to a mixture of 7:13

Let y be the factor

1:4=7:13y

13y = 28

y = 2.15 approximately

The amount of vinegar is to be increased by a factor of 2.15 the initial amount to get the desired ratio

12x2.15=25.8 approximately

So the amount of additional vinegar needed is 25.8-12=13.8 L approximately

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