Question

How many litres of water must be added to 20 liters of 10 percent solution of salt and water to produce a 6 percent of solution ​

Answer 1

Answer:

13(1/3) Litre.

Step-by-step explanation:

Given :-

Total Solution = 20 Litre .

Salt = 10% .

To Find :-

How Many litre of water must be added so That, 10% of salt becomes 6% in the solution ?

Solution :-

Total Solution = 20 litre .

Salt = 10%

Salt = 10% of 20 litre = (10*20)/100 = 2 Litre. ------- Equation(1).

Now, Lets Assume That, X Litre of water is Added .

Than,

Total Mixture = (20+x) Litre .

Salt = 6% .

Salt = 6% of (20+x) = [6*(20+x)] /100 Litre. ----- Equation(2)

Comparing Both Equations Now, we get,

[6*(20+x)] /100 = 2

6(20 + x) = 200

120 + 6x = 200

6x = 200 - 120

6x = 80

3x = 40

x = (40/3) = 13(1/3) Litre.

Hence, 13(1/3) Litre water must be added to make the salt 6% of the Solution..