Question

Two equal drops of water with radius T are falling through air with terminal velocities 'v coalesce to form a single drop. Compute the energy released in terms of r and surface tension T and the new terminal velocity. ​

Answer 1

Answer:

When the two equal drops coalesces, volume of water remains same and a bigger drop is formed. Lets say r is radius of drop before these combine and R is radius after these combine.

Step-by-step explanation:

2×

3

4

πr

3

=

3

4

πR

3

⇒R=2

1/3

r

and we know that terminal velocity V

T

∝ radius

2

, so we have

V

T

V

T

′

=

r

2

R

2

⇒V

T

′

=(

r

R

)

2

V

T

=(2

1/3

)

2

v

=2

2/3

v m/s