Question

in Thermodynamics system internal energy decrease by 100 j and 100 j
of work done is on the system then heat lost will be​

Answer 1

Answer:

A system is provided with 100J of heat : Work done on the system is 20J. What is the change in ΔE?

Answer 2

Answer:

The heat lost (Q) = -200J.

Explanation:

Taking the sign conventions from the system and not from the surroundings, we have

change in internal energy (ΔU)= -100J

work done on the system (W)  = +100J

Hence, using the first law of thermodynamics

The amount of energy in the universe is constant.

dU = dQ + dW

ΔU = Q + W.

Q is the heat gained by the system.

W is the work done on the system.

∴ The heat lost (Q) = -200J.

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21 MAY 2022.