How many metal sheets of seze1m×1m will be required to form a cylinder of height 14m and radials of the base 2m
Answers
201 metal sheets of size 1m×1m will be required to form a cylinder of height 14m and base radius of 2m.
Step-by-step explanation:
The dimension of each metal sheet = 1 m x 1 m
The dimensions of the cylinder to be formed:
Radius, r = 2 m
Height, h = 14 m
Therefore,
The no. of metal sheets required to form the cylinder is given by,
= [Surface area of the cylinder] / [Area of each metal sheet]
= [2πrh + 2πr²] / [side²]
= [{2*3.14*2*14} + {2*3.14*(2)²}] / [1²]
= [175.84 + 25.12]
= 200.96
≈ 201
Thus, 201 such metal sheets are required to form the cylinder of the given dimension.
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the number of metal sheets that will be required:201
1.the total surface area of a cylinder = 2πr^2+2π(r)h
where r is the radius of the base circle=2m
and h is the height of the cylinder=14m
2.the total surface area of the cylinder is =2π*2*2 + 2π(2)14
=200.96m^2
3.therefore 201 of 1m*1m metal sheets will be required to get the job done