How much pure alcohol should be added to 400ml of strength 15% to make its strength 32%
Answers
Answered by
1
Initial amount of alcohol is
\begin{lgathered}400 \times \frac{15}{100} = 60 \\\end{lgathered}
400×
100
15
=60
Let x ml of pure alcohol is to be added.
Then,
Amount of alcohol becomes 60 + x
Total amount of solution becomes 400 + x
\begin{lgathered}\frac{60 + x}{400 + x} \times 100 = 32 \\ 60 + x = 128 + 0.32x \\ 0.68x = 68 \\ x = 100 \: ml\end{lgathered}
400+x
60+x
×100=32
60+x=128+0.32x
0.68x=68
x=100ml
Answered by
0
Answer:
100 ml
Step-by-step explanation:
Similar questions