How many meters of canvas 1.25m wide will be needed to make a conical tent whose base radius is 17.5m and height is 6m
Answers
Answered by
161
Given :
Radius of cone (r)= 17.5 m
Height of cone(h) = 6 m
Slant height of cone(l) = √r²+h²
l = √6²+17.5²
l = √36 + 306.25 = √342.25
l= √342.25 = 18.5 m
Curved surface area of cone = πrl
= 22/7× 17.5 × 18.5
= 22× 2.5 ×18.5= 1017.5
Curved surface area of cone =1017.5 m²
Width of Canvas= 1.25 m
Length of Canvas required = C.S.A of Canvas / width of canvas
Length of Canvas required =1017.5/1.25 = 814 m
Length of Canvas required =814 m
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Hope this will help you.
Radius of cone (r)= 17.5 m
Height of cone(h) = 6 m
Slant height of cone(l) = √r²+h²
l = √6²+17.5²
l = √36 + 306.25 = √342.25
l= √342.25 = 18.5 m
Curved surface area of cone = πrl
= 22/7× 17.5 × 18.5
= 22× 2.5 ×18.5= 1017.5
Curved surface area of cone =1017.5 m²
Width of Canvas= 1.25 m
Length of Canvas required = C.S.A of Canvas / width of canvas
Length of Canvas required =1017.5/1.25 = 814 m
Length of Canvas required =814 m
==================================================================
Hope this will help you.
Answered by
56
Solution :-
Height of the cone = 6 m
Radius of the cone = 17.5 m
Slant height (l) = √r² + h²
⇒ √(17.5)² + (6)²
⇒ √306.25 + 36
⇒ √342.25
Slant height (l) = 18.5 m
Now, lateral surface area of cone = πrl
⇒ 22/7*17.5*18.5
= 7122.5/7
Lateral surface area of the cone = 1017.5 m²
Length of canvas of 1.25 m width will be needed to make the conical tent =
Lateral surface area of canvas/width of the canvas
⇒ 1017.5/1.25
⇒ 814 m
Hence, 814 m of canvas will be needed.
Height of the cone = 6 m
Radius of the cone = 17.5 m
Slant height (l) = √r² + h²
⇒ √(17.5)² + (6)²
⇒ √306.25 + 36
⇒ √342.25
Slant height (l) = 18.5 m
Now, lateral surface area of cone = πrl
⇒ 22/7*17.5*18.5
= 7122.5/7
Lateral surface area of the cone = 1017.5 m²
Length of canvas of 1.25 m width will be needed to make the conical tent =
Lateral surface area of canvas/width of the canvas
⇒ 1017.5/1.25
⇒ 814 m
Hence, 814 m of canvas will be needed.
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