How many miles of NaF must be dissolved is 1.00 l of a saturated solution of PbF2 at 25°c to reduce the [Pb2+] to 1x10^-6 molar? ( ksp of PbF2 at 25°c = 4.0x10^-8)
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Answer:
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Explanation:
PbF2 <-----> Pb2+ + 2 F-
4.0 x 10^-8 =1 x 10^-6 [F-]^2
[F-]= 0.2 M
Moles F- = 0.2 M x 1 L = 0.2
Mass NaF = 0.2 mol x 42 g/mol=8.4 g
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