How many milliliters of 2.5 m hcl are required to exactly neutralize 1.5 l of 5.0 m naoh?
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Answer:
3000 ml of. 2.5 M HCl is required.
Explanation ::
M1 × V1 = M2 × V2
X × 2.5 = 1500 × 5
X. = 3000
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