How many milliliters of an aqueous solution of 0.238 M iron(III) chloride is needed to obtain 18.8 grams of the salt?
_____mL
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Cooper Bromide is CuBr2, its molar mass 64+160= 224g/mol
0,147 mol of CuBr2 equil 224 g/mol x 0.147 mol =33 gram
In 1 L solution dissolved 33 g of salt, but we want to get 13.9 g of salt
therefore, 13.9 g will be in the aqueous solution of volume 0.42 L or 420 mL
( 13.9 / 33 = 0.42 L)
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