how many millilitres 6M HCL should be used to prepare 150 ml solution which is 0.3M in H + ions
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Answer:
this will contain3000ml.
Explanation:
M1V1=M2V2
6×150=0.3×V2
900/0.3=V2
900×10/3=V2
9000/3=V2
3000ml=V2
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