How many minimum meiosis divisions are essential for the formation of 126 zygotes in humans?
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minimum meoisis for 126 divisions
so for 126 zygoyes ..126 sperms are needed .. so rounding off 128/4 .. 32 meosis in testis
ovum .. total 126 ova are needed .. 1 oocyte gives 1 ovum by 2 meosis ..so total 126*2 = 252 meosis
hence total minimum meosis = 252 + 32 = 284
so for 126 zygoyes ..126 sperms are needed .. so rounding off 128/4 .. 32 meosis in testis
ovum .. total 126 ova are needed .. 1 oocyte gives 1 ovum by 2 meosis ..so total 126*2 = 252 meosis
hence total minimum meosis = 252 + 32 = 284
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