Math, asked by neerajkeshari1987, 11 months ago

How many ml of 30 percent acid should be added to pure acid to make 80 ml of 35 percent acid?

Answers

Answered by sakshi8918
1

Let x = number of ml of 60% acid

Since we are making up 50mL of solution, the amount of pure acid will be (50 - x)

x mL of 60% acid plus (50 - x )mL of 100% acid = 50 mL of 85% acid

0.60x + 1.00 (50 - x ) = 0.85(50)

0.60x + 50 - 1.00 x = 42.5

0.60x -1.00 x = -7.5

-0.40x = -7.5

x = 18.75

You need to add 18.75 mL of 60% solution to pure acid to make 50 mL of 85% acid.

Check: (18.75)(0.60) + 1.00(50-18.75) = 50(0.85)

11.25 + 31.25 = 42.5


sakshi8918: hi
sakshi8918: make me as BRINLIST
Similar questions