Question

How many mL of a 0.300 M AgNO3 solution will it take to make 500 mL of a 0.100 M AgNO3 solution?
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Answer 1

Answer:

We need 166, 7 mL of AgNO3 [0.300M] to prepare 500mL of AgNO3[ 0.100M]

Explanation:

When calculating the amount of volumen from an initial solution in order to prepare other one. we always use this formula for dilutions.

C1V1=C2V2

First we gather the information that will be replaced in our equation.

Inicial conditions that will be represented by  number 1

C1= 0.300M AgNO3

V1=  ?

Final conditions that will be represented by  number 2

C2= 0.100M AgNO3

V2=  500mL

Second, we replace the parameters giving in the equation and find out the value for V1.

V1= C2. V2 / C1

V1= 0.100M. 500mL /0.300M

V1= 166.7 mL

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