Question

) how many mole of o atoms are present in 88 gm co2 ?

Answer 1

Number of mole = amount  in g / molar mass

= 88 g / 44.01 G/ MOLE

= 1.99 or 2.0 mole CO2

1 Mole of CO2 = 2 Mole O

Therefore 2  mole CO2 * 2/1

= 4 Mole O

And 1 mole O = 6.022 *10^23 atoms

So 4 mole O * 6.022*10^23 atoms / 1 mole  

= 2.4*10^24 atoms O

Answer 2

There are 4 moles of oxygen atoms are present in 88 gm of $CO_2$

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{88g}{44g/mol}=2moles$

1 mole of $CO_2$ contains = 2 mole of oxygen atoms

Thus 2 mole of $CO_2$ contains =$\frac{2}{1}\times 2=4mole$ of oxygen atoms

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