how many molecule of water are present in 1g of water
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Avogadro's number 6.023 ×10^23
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1 mol of water = 18 g
6.022*10 to the power 23 molecules = 18 g
then 1 g = 6.022*10 to the power 23 molecules/18 g
= 0.33*10 to the power 23 molecules
6.022*10 to the power 23 molecules = 18 g
then 1 g = 6.022*10 to the power 23 molecules/18 g
= 0.33*10 to the power 23 molecules
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