Question

how many molecules and atoms of sulphur are present in 0.1 mole of s8 molecule

Answer 1

1 mole = 6.022 x 1023 molecules. Therefore, 0.1 moles = 0.1 x 6.022 x 1023. = 6.022 x 1022 molecules. Since 1 molecule of sulphur contains 8 atoms.
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Answer 2

Answer: $0.6023\times 10^{23}$ molecules of $S_8$ and $4.818\times 10^{23}$ atoms of $S_8$

Explanation:- According to avogadro's law, 1 mole of every substance  contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to the molecular mass of that substance.

Now 1 mole of $S_8$ molecule contains = $6.023\times 10^{23}$ molecules of $S_8$

Thus 0.1 moles of $S_8$ molecule contains = $\frac{6.023\times 10^{23}}{1}\times 0.1=0.6023\times 10^{23}$ molecules of $S_8$

1 mole of $S_8$ molecule contains = $8\times 6.023\times 10^{23}=48.18\times 10^{23}$ atoms of $S_8$

0.1 mole of $S_8$ molecule contains = $\frac{48.18\times 10^{23}}{1}\times 0.1=4.818\times 10^{23}$ atoms of $S_8$