how many molecules are present in 1.28g of so2 gas if the atomic mass of sulphur and oxygen is 32u and 16u respectively
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Answered by
16
mole=mass/molar mass
=1.28/64=0.02 mole
1 mole =6.022 . 10^23 molecules
0.02 mole= 6.022 .10^23 . 0.02 molecules
plz multiply this you can get ur answer
=1.28/64=0.02 mole
1 mole =6.022 . 10^23 molecules
0.02 mole= 6.022 .10^23 . 0.02 molecules
plz multiply this you can get ur answer
Answered by
17
1 mole = 6.02*10^23 moles
hence for 0.02 moles = 6.02*10^23 * 0.02
:: =12.04*10^21
hence for 0.02 moles = 6.02*10^23 * 0.02
:: =12.04*10^21
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