how many molecules are present in 1.28g of sulphur dioxide
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Molar mass of SO₂ is 64 g
64 g Sulphur dioxide contains 6.022 × 10²³ molecules
n = (1.28 g / 64 g) × 6.022 × 10²³ molecules
= 1.204 × 10²² molecules
∴ There are 1.204 × 10²² molecules in 1.28 g of Sulphur dioxide
64 g Sulphur dioxide contains 6.022 × 10²³ molecules
n = (1.28 g / 64 g) × 6.022 × 10²³ molecules
= 1.204 × 10²² molecules
∴ There are 1.204 × 10²² molecules in 1.28 g of Sulphur dioxide
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