Question

How many molecules are present in 16g N02

Answer 1

you multiply the number of moles present by Avagradro's constant, which is 6.022 x 10^23 particles per mole. This gives you an answer of 3.011 x 10^23 particles, and in this case the particles are diatomic oxygen molecules.

Answer 2

Answer:

$2.095\times {10}^{23}$

Explanation:

first we need to find moles of NO2.

moles of NO2 =16 / 46

=0.348 (approximately)

now, find molecules of NO2,

for this we Multiply moles with avogardo’s number

molecules of NO2=0.348× 6.022×10²³

=2.095×10²³