Math, asked by KuBo2313, 1 year ago

The difference between the sides at right angle in a right angle triangle is 14cm. The area of a triangle is 120cmsquare. Calculate the perimeter of the triangle.

Answers

Answered by kartik2507
5

Answer:

perimeter = 60cm

Step-by-step explanation:

area of right angle triangle = 1/2 × b × h = 120

let base = x height = y

x - y = 14

x = 14 + y

area = 120

120 =  \frac{1}{2}  \times x \times y \\ 120 =  \frac{1}{2}  \times (14 + y) \times y \\ 240 =  {y}^{2}  + 14y \\  {y}^{2}  + 14y - 240 = 0 \\  {y}^{2}  - 10y + 24y - 240 = 0 \\ y(y - 10) + 24(y - 10) = 0 \\ (y - 10)(y + 24) = 0 \\ y - 10 = 0 \:  \:  \:  \:  \:  \:  \:  \: y + 24 = 0 \\ y = 10 \:  \:  \:  \:  \: y =  - 24 \\

we take the positive value of y

x = y+14= 10+14= 24

by Pythagoras theorem

 {hyp}^{2}  =  {opp}^{2}  +  {adj}^{2}  \\  =  {24}^{2}  +  {10}^{2}  \\  = 576 + 100 \\  = 676 \\ hyp \:  =  \sqrt{676}  = 26

perimeter of triangle is

26 + 24 + 10 = 60cm

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