how many molecules are present in 5grams of CaCO3
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Answer:
Molecular mass of CaCO3 = 100 gm mol^-1
No. of molecules per mole = 6.022 x 10^23
5 gm CaCO3 = (6.022 x 10^23 x 5)/100
= 3.011 x 10^22 nos. of molecules.
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5.0 grams of calcium carbonate, or CaCO3 , can be converted to moles by using its molar mass. The molar mass is equal to 100.09 grams/mole (40.08 g...
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