Question

the digit in the unit's place of the number represented by 7^55-3^29 is?​

Answer 1

Answer:

Step-by-step explanation:

7^55-3^29

7^55: Cyclicity of 7 (unit digit when 7 is raised to the power of 1,2,3,4....) = 7,9,3,1...and same cycle continues

So, 7^55 = 55/4 (Rem = 3) so second number of the cyclicity i.e. 3 is the unit digit.

3^29: Cyclicity of 3 is 3,9,7,1.

So 3^29 = 29/3 (Rem = 2) so unit digit is 9

Question filters down to 3-9 = -6