how many molecules are present in 9g of h2o
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Answered by
10
m = 9 g
M = 18 g
no. of moles = m / M
= 9/18
= 1/2
n = N / Na
1/ 2 = N/ 6.022*10^ 23
N = 3.011 *10 ^ 23
M = 18 g
no. of moles = m / M
= 9/18
= 1/2
n = N / Na
1/ 2 = N/ 6.022*10^ 23
N = 3.011 *10 ^ 23
Answered by
0
1 mol have 18 g of molecules
1 g have 1/18 mol
9 g have 1/18 X 9
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