how many molecules are present in one drop of pure water which weights 0.05g
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Answered by
4
molecular mass of h2o is 18.
Now moles are equal to 0.05/18 is equal to0.0027.
now no of molecules is 0.0027 *6.022*10^23
Now moles are equal to 0.05/18 is equal to0.0027.
now no of molecules is 0.0027 *6.022*10^23
Answered by
2
Hey mate thank for the question
Hope it helps
Weight of pure drop water =0.05g
Molecular Mass of water =H20
MM of water =1×2+16
MM of water =18g
No of moles =weight/MM
No of moles =0.05/18
No of moles =.0.002
No of molecules =moles ×6.022×10^22
No of molecules=0.002×6.022×10^22
No of molecules=0.0120×10^22
No of molecules=1.20×10^20
Hope it helps
Weight of pure drop water =0.05g
Molecular Mass of water =H20
MM of water =1×2+16
MM of water =18g
No of moles =weight/MM
No of moles =0.05/18
No of moles =.0.002
No of molecules =moles ×6.022×10^22
No of molecules=0.002×6.022×10^22
No of molecules=0.0120×10^22
No of molecules=1.20×10^20
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