Question

How many molecules are there in 237 grams of ccl4

Answer 1

Answer:

9.28

⋅

10

23

molecules of

C

C

l

4

Explanation:

Using stoichiometry, we need to convert grams of

(

C

C

l

4

)

to moles, then moles to molecules.

237

g

⋅

1

mol

153.82

g

⋅

6.02

⋅

10

23

molecules

1

mol

=

9.28

⋅

10

23

molecules

Answer 2

1.32*10²⁶ molecules are there in 237 grams of ccl4

First of all, let us find the molar mass of CCl₄.

The molar mass of C is 12 gm and Cl is 35.5gm.

Thus, the molar mass of CCl₄ is = 12 + 4(35.5) gm

= 154gm.

We know that 1mole of any substance contains Avogadro number of molecules, which is 6.023*10²³.

So, 154 gm of CCl₄contains 6.023*10²³ molecules.

By unitary method, 1 gm of CCl₄ should contain (6.023*10²³/154) molecules.

Therefore 237 gm of CCl₄ will contain (6.023*10²³/154)*237 molecules

= 1.32*10²⁶ molecules.