How many molecules of an ideal gas at NTP occupies 11.2L
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22.4 l of ideal gas contains Na molecules
So, 11.2 l of ideal gas will contain 11.2Na/22.4 = Na/2 = 6.02*10^23 / 2 = 3.01*10^23 molecules
So, 11.2 l of ideal gas will contain 11.2Na/22.4 = Na/2 = 6.02*10^23 / 2 = 3.01*10^23 molecules
Answered by
1
1 mole occupies 22.4 l at NTP
11.2 l is occupied by 1/2 moles.
1 mole has 6.022×10^23 molecules.
So 1/2 moles have 3.011×10 ^23 molecules.
Hope this helps
11.2 l is occupied by 1/2 moles.
1 mole has 6.022×10^23 molecules.
So 1/2 moles have 3.011×10 ^23 molecules.
Hope this helps
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