Question

how many molecules of carbon dioxide are present in one litre of air containg 0.03% by volume of carbon dioxide at STP​

Answer 1

Answer:

8.065x10^18

Explanation:

22.4 L of gas at. stp= 1mole= 6.022 x 10^23 molecules

1L of gas at stp= 1/22.4= 0.0445moles

but CO2 is only 0.03%by volume

so no. of moles of CO2 = 0.0445 x 0.03/100=1.34 x 10^-5moles= 1.34x10^-5 x 6.022 x 10^23= 8.065 x 10^18 molecules