How many molecules of CH4 are in 24.1 g of this compound? A) 2.50 × 1024 B) 1.51 C) 9.08 × 1023 D) 1.45 × 1025
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mol. of CH4 =24.1/16
=1.5
since no. of molecules of CH4=no. of mol. of CH4 * Avogadro no.
=1.5*6.022*10^23
=9.03*10^23
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