Question

how many molecules of CO2 will be needed to obtain 1.8 g glucose according to given reaction.
6CO2 + 6H2O GIVES. C6H12O6 + 6O2 ​

Answer 1

Approximately 60 g of C6H12O6.

Explanation:

We have the balanced equation (without state symbols):

6H2O+6CO2→C6H12O6+6O2

So, we would need six moles of carbon dioxide to fully produce one mole of glucose.

Here, we got 88 g of carbon dioxide, and we need to convert it into moles.

Carbon dioxide has a molar mass of 44 g/mol. So here, there exist

88g44g/mol=2 mol

Since there are two moles of CO2, we can produce 26⋅1=13 moles of glucose (C6H12O6).

We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.

Glucose has a molar mass of 180.156 g/mol. So here, the mass of glucose produced is

13mol⋅180.156 gmol≈60 g to the nearest whole number.

So, approximately 60 grams of glucose will be produced.

Answer 2

• Answer:

• Approximately 60 g of C6H12O6.
• Explanation:
• We have the balanced equation (without state symbols):
• 6H2O+6CO2→C6H12O6+6O2
• So, we would need six moles of carbon dioxide to fully produce one mole of glucose.
• Here, we got 88 g of carbon dioxide, and we need to convert it into moles.
• Carbon dioxide has a molar mass of 44 g/mol. So here, there exist
• 88g44g/mol=2 mol
• Since there are two moles of CO2, we can produce 26⋅1=13 moles of glucose (C6H12O6).
• We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.
• Glucose has a molar mass of 180.156 g/mol. So here, the mass of glucose produced is
• 13mol⋅180.156 gmol≈60 g to the nearest whole number.
• So, approximately 60 grams of glucose will be produced.