Question

How many molecules of HCl are required to prepare 10gram of HCl

Answer 1

Answer:

1.67 molecules

Explanation:

GMM of hcl=36g

36g =6.022×10^23

10g=x

36×x=10×6.022×10^23

x= 10 × 6.022×10^23 ÷36

x=1.67 molecules of HCL.

hope it helps you

plzz follow me guys and thank me toooo