Question

​how many molecules of hcl gas will be produced by reacting 112 L of hydrogen at 0°C and 1 atm with 213 g of chlorine

Answer 1

Answer:

Explanation:

To get the molecules of HCl gas we must find out first the number of moles of HCl gas at STP.

To find out that we can simply use the formulae PV=nRT.

Where, P=1atm.

T=273K.

n we have to find out.

R=0.0821 .

Volume(V) given is 112L.

Thus, 1*112=n*0.0821*273

n=4.99=5 moles

Thus, there are 5 moles of hydrogen gas.

Now, to find out moles of chlorine gas.

n=given mass/molecular mass

n=213/70=3 moles approx

As,           H2+Cl2->2HCl

Thus, 1 mole each of hydrogen and chlorine gives 2 moles of HCl.

Thus,  3 moles of chlorine gas reacts with 3moles of hydrogen gas to give 6 moles of HCl as chlorine is the limiting reagent hence we use chlorine 3mole as limit.

Thus, molecules of chlorine gas is 6*6.023*10^22.