How many molecules of water is evolved when 387gms of gypsum is completely decomposed
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gypsum CaSO4.2H2O
here we see one mole gypsum contains 2mole water
now no of mole of gypsum=weight/molecular weight
=387/172=2.25mole
so, water contains 2x (2.25)=4.50mole
now use Avogadro laws
no of molecule =mole x avogadro constant
=4.5 x6.023 x10^23 molecules
here we see one mole gypsum contains 2mole water
now no of mole of gypsum=weight/molecular weight
=387/172=2.25mole
so, water contains 2x (2.25)=4.50mole
now use Avogadro laws
no of molecule =mole x avogadro constant
=4.5 x6.023 x10^23 molecules
abhi178:
if you like please mark as brainliest
No this is wrong
Answer is 27.09×10^23
Sorry this is correct answer I didn't see avagadro no.
please mark as brainliest
Thanks
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