Question

How many molecules of water of hydration are present in 39.2 mg of Mohr's salt?

Answer 1

molar mass = 392 g/mol

(39.2 mg) x (1 g/1000 mg) x (1mol / 392 g) x (6.022 x 1023 formula units / mole) x (6 molecules water / Formula unit) = 3.6132 x 1020 molecules.



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